Let ‘a’ be a positive number. Exponential notation is ax , where x is an integer. When x is a rational number, say p/q with p, an integer and q, a positive integer, we define ax by ax = root(q)(a) p
Example:
53/8 = root(3)(5)8
laws of exponents for real numbers: Exponents Notation
When x is an irrational number, ax can be defined to represent a real number.
For any a > 0, ax can be defined and that it represents an unique real number u and write u = ax.
The real number u is written in the exponential form or in the exponential notation.
Here the positive number 'a' is called the base and x, the index or the power or the exponent.
The laws of indices which we have stated for integer exponents can be obtained for all real exponents.
laws of Exponents for Real Numbers
We state them here and call them, the laws of exponents for real number:
root(x)(root(y)(a)) = root(xy)(a)
root(x)(a / b) = root(x)(a) / root(x)(b)
(root(x)(a) )x = a
axxx ay = ax+y
ax// ay = ax-y
(ax)y = axy
a-x = 1/ ax
axxx bx = abx
a0 = 1 for a != 0
(a/b)x = ax/bx
a1/x = root(x)(a)
(root(x)(a) )y/x = (root(x)(a) )
root(x)(a) root(x)(b) = root(x)(ab)
Example sums for Exponents for Real Numbers
Example 1:
Find the exponential form of (25)1/17
Solution of example 1:
Given = (25)1/17
Exponential form = root(17)(25)
Example 2:
Simplify 25225 / 53253
Solution of example 2:
Given 25225 / 53253
Now we use the exponents formula for real numbers
By using
(i)axxx ay = ax+y
(ii)axxx bx = abx
We get
= 253 / (5(25))3
= 253 / 1253
= 253 / (5)3(25)3
Cancel the same variables
Now, we get
= 1 / 53
= 1 / 125
Between, if you have problem on these topics Definition least Common Multiple, please browse expert math related websites for more help on sample paper of 9th class cbse.
Example 3:
Solve ( root(3)(root(2)(64))92xx 62) / ((43)2+(5/25)2)
Solution of example 3:
Given = ( root(3)(root(2)(64))92xx 62) / ((43)2+(5/25)2)
Now we use the exponents formula for real numbers
By using below laws of exponents formula we can simplify the given data.
(i) root(x)(root(y)(a)) = root(xy)(a)
(ii)axxx bx = abx
(iii)(ax)y = axy
(iv)(a/b)x = ax/bx
= ( root(3)(root(2)(64))92xx 62) / ((43)2+(5/25)2)
Use the (i) formula
We get
= root(6)(49))92xx 62) / ((43)2+(5/25)2)
Use the (ii) formula
We get
= ((root(6)(64))542) / ((43)2+(5/25)2)
Use the (iii) formula
We get
= ((root(6)(64))542) / ((46)+(5/25)2)
Use the (iii) formula
We get
= ((root(6)(64))542) / ((46)+(52/252))
= (2 (542) / ((256) + (25 / 252))
Cancel the same elements
We get
= 2(542) / ((256) + (1 / 25))
= 2(542) / ((6400 + 1) / 25 )
= 2(2916) / (6401/25)
= 2(2916)(25) / (6401)
= 50(2916) / 6401
= 145800 / 6401
= 22.77
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