quadratic equation examples

Let us solve quadratic equation examples.

There are 4 methods to solve quadratic equation. they are as follows;

1) Completing the Square, 2) Using the Quadratic Formula , 3) Factoring, 4) Square Root Method

Solve x² + x = 20 by factoring. And give a positive number only

Rewrite equation in standard form: x² + 2 x − 20 = 0

Factor the left side: (x + 5) (x − 4) = 0

Apply zero-product rule: x + 5 = 0 or x − 4 = 0

Solve for x in each equation: x = 4 and x =-5

Solve equation (3x −1)² − 9 = 0.

Apply square root method: (3 x − 1) ² = 9

3 x − 1 = √9 or 3x - 1 = − √9

3 x − 1 = 3 or 3 x − 1 = −3

Solve equations:

3x −1+1= 3 +1 or 3x -1+1= -3 +1

3 x = 4 or 3 x = −2

X = 4/3 or x = -2/3

In our next blog we shall learn about solving polynomial equations I hope the above explanation was useful.Keep reading and leave your comments.

galvanometer

Let us learn about galvanometer

Galvanometer is device used for measuring & detecting electric current. Galvanometer is an analog electromechanical transducer that produces a rotary deflection of some type of pointer in response to electric current flowing through its coil. The Galvanometer has expanded to include many uses of the same mechanism in positioning, recording, & servomechanism equipment.

The torque on a current roll in a uniform magnetic field is used to measure electrical magnetic field is used to measure electrical currents, the device used to measure current is called a moving coil galvanometer.

In our next blog we shall learn about kinetic energy formula I hope the above explanation was useful.Keep reading and leave your comments.

factors of 15

Let us find out factors of 15.

The factors of 15 are 1, 3, 5, and 15.
The prime factors of 15 are 3 and 5.

Find the products that represent the prime factorization of222.

Solution:

The prime factors of 222 are 2 and 3and 37 so:

222 = 2× 3 × 37

While you can observe, each factor is a prime number, so the answer should be right - the prime factorization of 222 is 2× 3 ×37.

In our next blog we shall learn about adding polynomials I hope the above explanation was useful.Keep reading and leave your comments.

geometric sequence

Let us learn geometric sequence.

geometric progression / geometric sequence, is a sequence of numbers where each term after the first is found by multiplying the previous one by a fixed non-zero number called the common ratio.

1. The 9^th term of an Arithmetic sequence is –7 and the 18^th term is 20. Find the sequence.

Solution:

t₉ = a + 8d = –7

t₁₈ = a + 17d = 20

t₁₈–t₉ gives 9d = 27

d = 3

Substituting d = 3 in t₉, we get

a + 24 = – 7,

a = – 31

Hence the Arithmetic sequence. is -31, -28, -25,…

In our next blog we shall learn how to make a pie chart I hope the above explanation was useful.Keep reading and leave your comments.

height converter

Let us learn about height converter

Height converter is specified in either centimeter, meters , feet and inches. The height & weight can be converted from centimeter to feet, meter into feet and etc. in conversion the unit is mentioned such as cm or feet.

1 centimeter = 0.033 feet

1 feet = 30.48 centimeter, same like

Height converter Cm to feet

2 centimeter = 0.065 616 797 9 feet

3 centimeter = 0.098 425 196 85 feet

Feet to cm

2 feet = 60.96 centimeter

3 feet = 91.44 centimeter

In our next blog we shall learn about granite gradebook I hope the above explanation was useful.Keep reading and leave your comments.

linear equations in two variables

Let us learn about linear equations in two variables

In algebra we represent a unknown number by using variables. We use letters to denote variables. A linear equation in two variables is of the form

ax + by = c,

where a ≠ 0, b ≠ 0

Linear equations in Two Variables Example

2x + 3y = 5,

x - 2y = 6,

-6x + y =8

A pair of values of y and x that satisfy a given linear equation in two variables is said to be its solution.

In our next blog we shall learn about point slope form I hope the above explanation was useful.Keep reading and leave your comments.

Area of a Triangle

Hi Friends!!!

In our previous blog we learned about the area of a circle and now let us learn about Area of a Triangle.

A triangle is a three-sided polygon. Area of the triangle is half of the multiplication of base and height of the triangle.

Find the area of triangle with a base of 15 cm and a height of 4 cm

Area of a triangle formula = Area = 1/2(b*h)

Substitute the values of base and height. Then we get,

= 1/2(15*4)

Multiplying the values of base and height and then dividing by 2.Then we get final answer.

= 1/2(60)

= 30 cm²

I hope the above explanation was useful.Keep reading and leave your comments.