Normally zeros of a function mean when we plug the values for the variables the functions values tends to be zero. Let us consider if we are having a function with variable x and we have a set of solution p(x) if we plug the solution for the given variables present in the function we will get the function f(x) = 0. To find the rational zeros we have to use the rational zeros theorem.
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Rational Zeros of a Function – Examples:
The rational theorem states that if we are having the polynomial p(x) wit the integer coefficients and we are having the zeros of the polynomial `p / q` then we can say `p(p / q) = 0` . Here p is nothing but the constant term of the polynomial and the q I nothing but the leading coefficient of the polynomial p(x). We will see some examples for finding the rational zeros of a function.
Example 1 for rational zeros of a function:
Find the rational zeros of the following function.
2x2 + 12x + 10
Solution:
The given function is
2x2 + 12x + 10
First we have to find the rots of the constant term. ±1, ±2, ±5, ±10
Now the leading co – efficient of the constant term is 2. So we have to divide by 2.
±`p / q` = ±`1/ 2` , ±`2/ 2` , ±`5/ 2` , ±`10/ 2`
= ±`1/2` , ±1, ±`5/2` , ±5
Now we have to use the synthetic division method to find the rational zeros.
1 / 2 | 2 12 10
| 1 13/2
|_____________________
2 13 33/2 = not a zero
-1 / 2 | 2 12 10
| -1 -11/2
|_____________________
2 11 9/2 = not a zero
1 | 2 12 10
| 2 24
|_____________________
2 24 34 = not a zero
-1 | 2 12 10
| -2 -10
|_____________________
2 10 0 = is a zero
5/2 | 2 12 10
| 5 85/2
|_____________________
2 17 105/2 = not a zero
- 5/2 | 2 12 10
| -5 -35/2
|_____________________
2 7 15/2 = not a zero
5 | 2 12 10
| 10 110
|_____________________
2 22 120 = not a zero
-5 | 2 12 10
| -10 -10
|_____________________
2 2 0 = is a zero
So from the above the rational zeros of the functions are p(x) is -1 and -5
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Rational Zeros of a Function – more Examples:
Example 2 for rational zeros of a function:
Find the rational zeros of the following function.
x2 + 4x + 3
Solution:
The given function is
x2 + 4x + 3
First we have to find the rots of the constant term. ±1, ±3
Now the leading co – efficient of the constant term is 1. So we have to divide by 1.
±`p / q` = ±`1/ 1` , ±`3 / 1`
= ±1, ±3
Now we have to use the synthetic division method to find the rational zeros.
1 | 1 4 3
| 1 5
|_____________________
1 5 8 = not a zero
-1| 1 4 3
| -1 -3
|_____________________
1 3 0 = is a zero
3 | 1 4 3
| 3 21
|_____________________
1 7 24 = not a zero
-3| 1 4 3
| -3 -3
|_____________________
1 1 0 = is a zero
So from the above the rational zeros of the functions are p(x) is -1 and -3
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