Cube is not a polygon,because cube is a three dimensional shaped figure .But polygon is a two dimensional object. Generally polygon must be flat, plane figure and it’s made up of line segment. Here we are going to study about cube and polygon shape and its example problems.
Shape of cube:
Cube is a regular solid three-dimensional figure it has six square faces .it has 12 edges of equal length and 8 vertices it is otherwise called as regular hexahedron.
Shape of polygon:
It will be triangle, quadrilateral, pentagon, hexagon, octagon, heptagon…etc. All are two dimensional shapes.
Example problems for cube:
Example: 1
Find the volume of the cube with side length 6 meter.
Solution:
We know that volume of the cube is a 3
Given a = 6
Therefore a3 = (6)3
= 6 * 6 * 6
= 216 meter cube
Example: 2
Find the surface area of the cube each side length of a cube is 16 feet.
Solution:
We know that surface area of cube is,
A = 6a2
Here the given a = 16 feet
Substitute the a value in the above formula we get
A= 6*162
162 = 16*16 = 256
Therefore the area of the cube is
= 6*256
=1536 feet square
The surface area of the given cube is 1536 feet square.
Example problems for polygon:
Example: 1
Find the perimeter of the polygon which is hexagon shape with side length is 9 feet
Solution:
We know that perimeter of the hexagon is =6*a
a represents the side length
Therefore perimeter = 6 *9
= 54
Perimeter of the given hexagon is 54 feet
My forthcoming post is on syllabus of class x cbse and tamil nadu text book will give you more understanding about Algebra.
Example: 2
Find the perimeter of the regular pentagon with side length is 8 meter
Solution:
We know that pentagon is one of a polygon and formula for finding the perimeter is 5 *a
= 5 * 8
= 40
Perimeter of the pentagon is = 40 meter
Shape of cube:
Cube is a regular solid three-dimensional figure it has six square faces .it has 12 edges of equal length and 8 vertices it is otherwise called as regular hexahedron.
Shape of polygon:
It will be triangle, quadrilateral, pentagon, hexagon, octagon, heptagon…etc. All are two dimensional shapes.
Example problems for cube:
Example: 1
Find the volume of the cube with side length 6 meter.
Solution:
We know that volume of the cube is a 3
Given a = 6
Therefore a3 = (6)3
= 6 * 6 * 6
= 216 meter cube
Example: 2
Find the surface area of the cube each side length of a cube is 16 feet.
Solution:
We know that surface area of cube is,
A = 6a2
Here the given a = 16 feet
Substitute the a value in the above formula we get
A= 6*162
162 = 16*16 = 256
Therefore the area of the cube is
= 6*256
=1536 feet square
The surface area of the given cube is 1536 feet square.
Example problems for polygon:
Example: 1
Find the perimeter of the polygon which is hexagon shape with side length is 9 feet
Solution:
We know that perimeter of the hexagon is =6*a
a represents the side length
Therefore perimeter = 6 *9
= 54
Perimeter of the given hexagon is 54 feet
My forthcoming post is on syllabus of class x cbse and tamil nadu text book will give you more understanding about Algebra.
Example: 2
Find the perimeter of the regular pentagon with side length is 8 meter
Solution:
We know that pentagon is one of a polygon and formula for finding the perimeter is 5 *a
= 5 * 8
= 40
Perimeter of the pentagon is = 40 meter
No comments:
Post a Comment